Class 10 Maths Chapter 7: Coordinate Geometry case study question with answers
One case-based question of the kind the board asks in Section E: a passage and a figure, then 3 parts worth 4 marks in all, with the answer and the marking scheme for each. Written from the NCERT chapter.
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Answer: (b) 20 km
HS = √(12² + 16²) = √400 = 20 km. (28 adds the gaps; 2√41 = √164 adds the coordinates instead of subtracting them.)
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Answer: (b) (4, 5)
Mid-point = ((−2 + 10)/2, (−3 + 13)/2) = (4, 5). (6, 8) halves the differences instead of the sums.
Answer and marking scheme
B = ((3 × 10 + 1 × (−2))/4, (3 × 13 + 1 × (−3))/4) = (28/4, 36/4) = (7, 9).
- applies the section formula with m₁ = 3, m₂ = 1 (1)
- B = (7, 9) (1)
Answer and marking scheme
HT = 5 km and HS = 20 km, so HT = (1/4)HS and HT : TS = 1 : 3 (the ratio of the parts, not 1 : 4). T = ((1 × 10 + 3 × (−2))/4, (1 × 13 + 3 × (−3))/4) = (1, 1).
- HT : TS = 1 : 3 from HT = (1/4)HS (1)
- T = (1, 1) (1)
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