Class 10 Science Chapter 11: Electricity MCQs with answers
10 multiple-choice questions on Electricity, each with its answer and the reason, written from the NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (a) 3 A
I = Q/t = 270 C / (1.5 × 60 s) = 270/90 = 3 A, and 1 A = 1 C/s. 180 A leaves the time in minutes; 0.33 A divides t by Q; 405 A multiplies Q by t.
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Answer: (c) an ammeter and a voltmeter
An ammeter is always connected in series with the part whose current it measures; a voltmeter is always connected in parallel across the two points whose potential difference it measures.
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Answer: (a) 4 C
Each electron carries 1.6 × 10⁻¹⁹ C, so Q = 2.5 × 10¹⁹ × 1.6 × 10⁻¹⁹ C = 4 C.
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Answer: (d) 12 V
V = W/Q = 360 J / 30 C = 12 J/C = 12 V. Multiplying (10800) or inverting the ratio (0.083) are the usual slips.
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Answer: (c) the closed path is broken, so the current stops
A circuit is a continuous closed path; opening the switch breaks it, the current stops and the bulb does not glow. The cells keep their potential difference, and electrons are not used up.
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Answer: (c) flows from the positive terminal through the bulb to the negative terminal
Conventional current is taken opposite to the flow of electrons, so in the external circuit it is shown from the positive terminal to the negative terminal.
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Answer: (b) a straight line through the origin
At constant temperature V is directly proportional to I for a metallic conductor, so the V-I graph is a straight line passing through the origin.
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Answer: (a) 0.2 A
I = V/R: with V unchanged, three times the resistance gives one-third the current, 0.6 A / 3 = 0.2 A.
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Answer: (b) a rheostat
A rheostat changes the resistance in a circuit without changing the voltage source, so it changes the current through the lamp.
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Answer: (a) 3.5 Ω
R ∝ l. The piece is 0.5 m / 2 m = 1/4 of the length, so R = 14 Ω / 4 = 3.5 Ω.
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