Class 10 Science Chapter 13: Our Environment case study question with answers
One case-based question of the kind the board asks in Section E: a passage and a table, then 3 parts worth 4 marks in all, with the answer and the marking scheme for each. Written from the NCERT chapter.
| Trophic level | Organism | Energy (kJ per m² per year) |
|---|---|---|
| I | phytoplankton | 12 000 |
| II | zooplankton | 1200 |
| III | small fish | 120 |
| IV | fish-eating bird | ? |
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Answer: (b) 12 kJ
Each level holds about 10% of the one below: 12 000 → 1200 → 120, so 10% of 120 = 12 kJ. 108 kJ is 120 less 10%, the reverse slip.
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Answer: (c) small fish
Zooplankton feed on the producers and are primary consumers; the small fish eat them and, at level III, are the secondary consumers.
Answer and marking scheme
In the fish-eating bird. The pesticide is not degradable, so it accumulates at each trophic level, and the concentration is greatest at the top of the chain: biological magnification.
- fish-eating bird (1)
- accumulates at each level as it is not degraded (biological magnification) (1)
Answer and marking scheme
The birds receive only about 12 kJ against 120 kJ for the small fish: only about 10% of the energy passes from one level to the next. So the higher level can support far fewer individuals, and numbers fall at each step up the chain.
- only about 10% of energy passes up (12 kJ against 120 kJ) (1)
- less energy supports fewer individuals at the higher level (1)