Class 10 Science Chapter 9: Light: Reflection and Refraction MCQs with answers
10 multiple-choice questions on Light: Reflection and Refraction, each with its answer and the reason, written from the NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (b) 55°
Angles of incidence and reflection are measured from the normal. The ray makes 90° − 35° = 55° with the normal, so i = 55° and, since the angle of incidence equals the angle of reflection, r = 55°.
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Answer: (c) 1.6 m
She is now 1.2 − 0.4 = 0.8 m from the mirror. A plane-mirror image is as far behind the mirror as the object is in front, so the image is 0.8 m behind it and the separation is 0.8 + 0.8 = 1.6 m.
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Answer: (d) 28 cm
The bright spot is the real image of the distant Sun, formed at the principal focus, so f ≈ 14 cm. For a mirror of small aperture R = 2f = 28 cm.
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Answer: (a) P only
The pole is the centre of the reflecting surface and lies on the mirror. F and C lie on the principal axis in front of a concave mirror, not on its surface.
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Answer: (d) appear to diverge from a point on the principal axis behind the mirror
A convex mirror reflects parallel rays so that they appear to come from a point on the principal axis behind the mirror; that point is its principal focus.
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Answer: (b) between F and C; diminished, real and inverted
C is at 2f = 20 cm, so the bulb at 35 cm is beyond C. With the object beyond C a concave mirror forms the image between F and C: diminished, real and inverted.
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Answer: (d) virtual, erect and enlarged
With the object between the pole and the focus, a concave mirror forms an enlarged, virtual and erect image behind the mirror; that is why dentists use it to see large images of teeth.
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Answer: (d) a convex mirror
A convex mirror always forms an erect, diminished image, so a small one can show a full-length image of a large object such as a tall building; a plane or concave mirror of the same size cannot.
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Answer: (c) is reflected back along the same path
A ray directed towards the centre of curvature strikes the mirror along the normal, so it is reflected straight back along the same path.
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Answer: (b) 50°
At the pole the principal axis is the normal. The reflected ray makes 25° with the axis on the other side, so the angle between the two rays is 25° + 25° = 50°.
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