Class 11 Maths Chapter 6: Permutations and Combinations MCQs with answers
10 multiple-choice questions on Permutations and Combinations, each with its answer and the reason, written from the NCERT chapter. For school exams on the CBSE pattern and JEE Main, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (b) 12
A train can be chosen in 4 ways, and after it a bus in 3 ways; by the multiplication principle, 4 × 3 = 12. Adding (7) treats the two choices as alternatives, not as events in succession.
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Answer: (c) 243
Each of the 5 letters has 3 choices of box, and a box may take any number of letters, so the count is 3 × 3 × 3 × 3 × 3 = 35 = 243. 53 gives each box a choice of letter, which is the wrong way round.
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Answer: (d) n(n + 1)
(n + 1)! = (n + 1) × n × (n − 1)!, so the quotient is (n + 1)n = n(n + 1).
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Answer: (b) 10
0! = 1 by definition, 1! = 1, 2! = 2, 3! = 6; the sum is 1 + 1 + 2 + 6 = 10. Taking 0! as 0 gives 9.
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Answer: (a) 210
The medals are different, so order matters: ⁷P₃ = 7 × 6 × 5 = 210. ⁷C₃ = 35 ignores which medal goes to whom; 73 lets one runner win twice.
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Answer: (a) 105
¹⁵C₁₃ = ¹⁵C₂ = 15 × 142 = 105. 210 is ¹⁵P₂, the count without dividing by 2!.
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Answer: (c) 36
A game is fixed by its pair of players, and the pair A, B is the same as B, A: ⁹C₂ = 9 × 82 = 36. 72 counts each game twice.
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Answer: (d) 360
By Theorem 3, n!/p! = 6!/2! = 720/2 = 360.
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Answer: (b) Choosing 3 members of a committee from 10 people
In a committee the members have no order: the committee of X, Y, Z is the same as Z, Y, X. The other three are arrangements in which order changes the outcome.
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Answer: (c) 3
ⁿP₀ = 1, ⁿCn = 1 and 0! = 1, so the sum is 1 + 1 + 1 = 3.
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