Class 12 Chemistry Chapter 4: The d- and f-Block Elements MCQs with answers
10 multiple-choice questions on The d- and f-Block Elements, each with its answer and the reason, written from the NCERT chapter. For the CBSE board, JEE Main and NEET, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (d) 3d¹⁰4s¹
A completely filled 3d set is relatively more stable, so one 4s electron moves into 3d: Cu is [Ar]3d¹⁰4s¹, not 3d⁹4s².
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Answer: (a) [Ar]3d⁶
Co is [Ar]3d⁷4s². On ionisation the two 4s electrons leave first, then one 3d electron: Co³⁺ is [Ar]3d⁶, with no 4s electrons.
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Answer: (a) Ag²⁺
A transition element has an incompletely filled d subshell in at least one of its common oxidation states. Zn²⁺, Cd²⁺ and Hg²⁺ are all d¹⁰; Ag²⁺ is 4d⁹, so silver, through Ag(II), qualifies while zinc, cadmium and mercury do not.
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Answer: (d) +5
Up to manganese the maximum state equals the number of s plus d electrons: V is 3d³4s², 3 + 2 = 5, as in VO₂⁺.
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Answer: (a) +6
x + 4(−2) = −2, so x = +6. Ferrate(VI) decomposes readily to Fe₂O₃ and O₂, which is why no iron oxide above Fe₂O₃ is known.
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Answer: (c) Mn²⁺
Aquated Mn²⁺ is pink; Ni²⁺ is green, Cr³⁺ violet and Cu²⁺ blue.
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Answer: (d) Sc³⁺, Ti⁴⁺, Zn²⁺
Sc³⁺ and Ti⁴⁺ are 3d⁰ and Zn²⁺ is 3d¹⁰: none can have a d–d transition. Ti³⁺ (3d¹, purple), Fe³⁺ (3d⁵, yellow) and Cu²⁺ (3d⁹, blue) are coloured.
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Answer: (d) Ti²⁺ and Ni²⁺
μ = √(n(n+2)) BM for n unpaired electrons. Ti²⁺ (d²) and Ni²⁺ (d⁸) both have two unpaired electrons: √8 = 2.84 BM. V²⁺ (d³) 3.87 against Mn²⁺ (d⁵) 5.92; Cr²⁺ (d⁴) 4.90 against Fe³⁺ (d⁵) 5.92; Co²⁺ (d⁷) 3.87 against Cu²⁺ (d⁹) 1.73.
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Answer: (d) chromium (Z = 24)
3.87 BM = √(3 × 5), so n = 3. M³⁺ has (Z − 21) d electrons: V³⁺ d² (2 unpaired, 2.84), Cr³⁺ d³ (3 unpaired, 3.87), Mn³⁺ d⁴ (4, 4.90), Fe³⁺ d⁵ (5, 5.92). Only chromium fits.
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Answer: (a) Zr and Hf
Because of the lanthanoid contraction the 4d and 5d members of a group have nearly the same radii: Zr 160 pm, Hf 159 pm. Down from 3d to 4d (Ti to Zr, Sc to Y, Cu to Ag) the radius increases.
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