Class 12 Maths Chapter 3: Matrices case study question with answers
One case-based question of the kind the board asks: a passage and a table, then 3 parts worth 4 marks in all, with the answer and the marking scheme for each. Written from the NCERT chapter.
| Matrix | Entries |
|---|---|
| S | [[120, 40, 10], [90, 60, 15]] |
| P | [[56], [80], [600]] |
| C | [[48], [65], [520]] |
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Answer: (a) order 2 × 1
S is 2 × 3 and P is 3 × 1; the columns of S equal the rows of P, and SP is 2 × 1.
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Answer: (a) ₹18,840
Row 2 of S times P: 90(56) + 60(80) + 15(600) = 5040 + 4800 + 9000 = ₹18,840.
Answer and marking scheme
P − C = [[8], [15], [80]]. S(P − C) = [[120(8) + 40(15) + 10(80)], [90(8) + 60(15) + 15(80)]] = [[960 + 600 + 800], [720 + 900 + 1200]] = [[2360], [2820]]. Total daily profit = 2360 + 2820 = ₹5,180.
- P − C = [[8], [15], [80]] and S(P − C) = [[2360], [2820]] (1)
- total ₹5,180 (1)
Answer and marking scheme
SC = [[120(48) + 40(65) + 10(520)], [90(48) + 60(65) + 15(520)]] = [[5760 + 2600 + 5200], [4320 + 3900 + 7800]] = [[13560], [16020]]. SP = [[15920], [18840]], so SP − SC = [[2360], [2820]]: ₹2,360 and ₹2,820. By the distributive law, SP − SC = S(P − C).
- SC = [[13560], [16020]] (1)
- profits ₹2,360 and ₹2,820, distributive law named (1)
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