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Class 12 Maths Chapter 7: Integrals MCQs with answers

10 multiple-choice questions on Integrals, each with its answer and the reason, written from the NCERT chapter. For the CBSE board and JEE Main, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.

Question 1
∫ (sec x tan x + 2x) dx equals
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Answer: (b) sec x + x2 + C

d/dx (sec x) = sec x tan x and d/dx (x2) = 2x, so ∫ (sec x tan x + 2x) dx = sec x + x2 + C.

Question 2
∫ 5x dx equals
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Answer: (a) 5xlog 5 + C

∫ ax dx = axlog a + C; with a = 5 the integral is 5xlog 5 + C. The power rule does not apply, since the variable is in the exponent.

Question 3
F is an anti derivative of f(x) = 6x2 − 4x + 1 with F(1) = 5. Then F(2) equals
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Answer: (c) 14

F(x) = 2x3 − 2x2 + x + C. F(1) = 1 + C = 5 gives C = 4, so F(2) = 16 − 8 + 2 + 4 = 14.

Question 4
If ∫ f(x) dx = x2 log x + C, x > 0, then f(x) is
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Answer: (c) x(2 log x + 1)

Since ddx ∫ f(x) dx = f(x), f(x) = ddx(x2 log x) = 2x log x + x2 · 1x = x(2 log x + 1).

Question 5
∫ cosec x dx equals
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Answer: (c) log |cosec x − cot x| + C

Multiplying and dividing by (cosec x − cot x) and putting cosec x − cot x = t gives ∫ cosec x dx = log |cosec x − cot x| + C. Option (d) is ∫ cot x dx; (a) is the derivative of cosec x.

Question 6
∫ dxx2 + 25 equals
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Answer: (b) 15 tan-1 x5 + C

∫ dxx2 + a2 = 1a tan-1 xa + C with a = 5. Option (d) is the form for x2 − 25.

Question 7
∫13 (2x + 1) dx equals
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Answer: (d) 10

An anti derivative is F(x) = x2 + x. F(3) − F(1) = 12 − 2 = 10.

Question 8
∫−11 (x5 cos x + 3x2) dx equals
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Answer: (d) 2

x5 cos x is odd, so its integral over [−1, 1] is 0 by P₇; 3x2 is even, so it contributes 2∫01 3x2 dx = 2. The value is 2.

Question 9
If F(x) = ∫1x (t3 − 2t + 4) dt, then F′(2) equals
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Answer: (a) 8

By the first fundamental theorem, F′(x) = x3 − 2x + 4, so F′(2) = 8 − 4 + 4 = 8. Option (b) is F(2), and (c) differentiates the integrand.

Question 10
∫ (cos 4x − e−x) dx equals
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Answer: (b) 14 sin 4x + e−x + C

ddx(14 sin 4x) = cos 4x and ddx(e−x) = − e−x, so the integral is 14 sin 4x + e−x + C.

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