Class 12 Maths Chapter 9: Differential Equations MCQs with answers
10 multiple-choice questions on Differential Equations, each with its answer and the reason, written from the NCERT chapter. For the CBSE board and JEE Main, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (d) 2
The derivatives present are d²y/dx² (order 2) and dy/dx (order 1); the order is that of the highest order derivative, 2. Options (b) and (c) read the powers 3 and 4 as orders.
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Answer: (c) 2
The equation is a polynomial in y′ and y″. The highest order derivative is y″, and its highest power is 2, so the degree is 2. Option (b) takes the highest power of any derivative; (d) adds the two powers.
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Answer: (b) y′ + ey′ = x
ey′ is not a polynomial in y′, so (b) is not a polynomial equation in its derivatives and its degree is not defined. In (a) cos y involves y, not a derivative, so (a) is a polynomial in y″ of degree 1; (c) has degree 2 and (d) degree 1.
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Answer: (b) 2
A general solution has as many arbitrary constants as the order of the equation. Here there are two, a and b, so the order is 2.
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Answer: (d) y = 3 cos 2x
For y = 3 cos 2x, y″ = −12 cos 2x, so y″ + 4y = 0, and it has no arbitrary constant: a particular solution. (b) also satisfies the equation but carries the arbitrary constants A, B, so it is the general solution. For (c), y″ + 4y = −36 cos 4x ≠ 0; for (a), y″ + 4y = 8e2x ≠ 0.
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Answer: (b) 4
y′ = m xm−1, y″ = m(m − 1) xm−2. Substituting: [m(m − 1) − 2m − 4] xm = 0, so m2 − 3m − 4 = 0, (m − 4)(m + 1) = 0. The positive root is m = 4.
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Answer: (c) 5
The highest order derivative is d³y/dx³, so the order is 3; its power is 2, so the degree is 2. The sum is 5. Option (b) uses the power 5 of the second derivative as the degree.
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Answer: (c) x2 + y2 = 4x
A differential equation must involve a derivative of the dependent variable. x2 + y2 = 4x contains none; (b) is the equation x dy/dx + y = 0 written with differentials.
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Answer: (d) ey = x22 + C
Separating, ey dy = x dx. Integrating both sides: ey = x2/2 + C. Option (b) integrates ey wrongly as e−y; (c) drops the factor 1/2.
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Answer: (c) y = C(1 + x2)
Separating, dy/y = 2x dx/(1 + x2). Integrating: log y = log (1 + x2) + log C, so y = C(1 + x2). Option (a) forgets that the constant multiplies after taking exponentials.
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