Class 12 Physics Chapter 13: Nuclei case study question with answers
One case-based question of the kind the board asks: a passage and a figure, then 3 parts worth 4 marks in all, with the answer and the marking scheme for each. Written from the NCERT chapter.
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Answer: (b) is short-ranged, so an interior nucleon is bound only by its near neighbours
Saturation: with a short-ranged force, an interior nucleon's binding does not grow with the size of the nucleus, and most nucleons are interior. Charge independence, strength and the repulsive core are true properties but do not explain the flat region.
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Answer: (c) 8.6
Fusion: 4 × 7.1 − 2 × (2 × 1.1) = 24.0 MeV from 4 nucleons, 6.0 MeV per nucleon. Fission: 180 × (8.7 − 8.0) = 126 MeV from 180 nucleons, 0.70 MeV per nucleon. Ratio 6.0/0.70 ≈ 8.6. 0.19 compares the energies per reaction (24/126), not per nucleon.
Answer and marking scheme
⁵⁶Fe sits at the peak of the curve, Ebn ≈ 8.75 MeV. Splitting it gives lighter nuclei with lower Ebn, and fusing two such nuclei gives a heavier one with lower Ebn. Either way the nucleons end up less tightly bound, the products have more mass than the reactants, the Q-value is negative, and energy has to be supplied.
- ⁵⁶Fe at the peak: the products of either process have lower E_bn (1)
- less binding means more mass: negative Q-value, energy must be supplied (1)
Answer and marking scheme
Fusing two nuclei releases energy only when the product has a higher Ebn than the reactants. Ebn rises with A up to the peak near A = 56 (⁵⁶Fe, 8.75 MeV) and falls beyond it, so fusion beyond the peak would absorb energy rather than release it; elements more massive than those near the peak cannot be made this way.
- fusion releases energy only if E_bn rises (1)
- E_bn falls beyond A ≈ 56, so fusion there absorbs energy (1)
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