Physics · Optics · chapter 9 of 14

Class 12 Physics Chapter 9: Ray Optics and Optical Instruments MCQs with answers

10 multiple-choice questions on Ray Optics and Optical Instruments, each with its answer and the reason, written from the NCERT chapter. For the CBSE board, JEE Main and NEET, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.

Question 1
A small object stands in front of a convex mirror. In the Cartesian sign convention, the object distance u and the focal length f of the mirror are
Show answer

Answer: (c) u negative, f positive

Distances are measured from the pole, positive along the incident light. The object is on the side the light comes from, so u is negative; the focus of a convex mirror lies behind it, along the incident light, so f is positive.

Question 2
A refracting telescope in normal adjustment is 93 cm long and has a magnifying power of 30. The focal length of its eyepiece is
Show answer

Answer: (a) 3.0 cm

In normal adjustment the tube length is fo + fe = 93 cm and the magnifying power is fo/fe = 30, so fo = 30 fe and 31 fe = 93 cm, fe = 3.0 cm (fo = 90 cm). 3.1 cm comes from dividing the length by 30, forgetting that the length also contains fe; 90 cm is the objective.

Question 3
A ray of light travelling towards the centre of curvature of a convex mirror strikes the mirror. After reflection the ray
Show answer

Answer: (d) retraces its path

A ray directed towards the centre of curvature meets the mirror along the normal (the radius), so the angle of incidence is zero and the ray is reflected back along its own path.

Question 4
A concave mirror forms on a screen a sharp real image of a small lamp. The lamp is 18 cm and the screen 36 cm in front of the mirror, both on its principal axis. In the Cartesian sign convention the focal length of the mirror is
Show answer

Answer: (b) −12 cm

Object and real image are both in front of the mirror, so u = −18 cm and v = −36 cm. 1/f = 1/v + 1/u = −1/36 − 1/18 = −3/36, f = −12 cm. +12 cm drops the sign of a concave mirror; −27 cm is the average of the two distances, not a focal length.

Question 5
A convex mirror of focal length 20 cm forms an image of an object that is 0.4 times the height of the object. The distance of the object from the mirror is
Show answer

Answer: (b) 30 cm

The image of a convex mirror is erect, so m = +0.4. With m = −v/u and 1/v + 1/u = 1/f, m = f/(f − u), so u = f − f/m = 20 − 50 = −30 cm: the object is 30 cm in front of the mirror (and v = +12 cm). 12 cm is the image distance; 50 cm is f/m alone; 8.0 cm is f × m.

Question 6
An object on the axis of a concave mirror of focal length 10 cm is moved from 30 cm to 20 cm in front of the mirror. During this move the image shifts through
Show answer

Answer: (d) 5 cm, away from the mirror

f = −10 cm. At u = −30 cm, 1/v = −1/10 + 1/30 = −1/15, v = −15 cm. At u = −20 cm, 1/v = −1/10 + 1/20 = −1/20, v = −20 cm. The image moves from 15 cm to 20 cm in front of the mirror: 5 cm away from it, as the object moves 10 cm towards it.

Question 7
The refractive index of a piece of glass with respect to air depends on
Show answer

Answer: (a) the wavelength of the light

n21 is a property of the pair of media and depends on the wavelength of light, not on the angle of incidence. Because it differs for different colours, white light splits into its colours (dispersion).

Question 8
Take c = 3.0 × 10⁸ m s⁻¹. The refractive index of a transparent plastic with respect to vacuum is 1.25. The speed of light in the plastic is
Show answer

Answer: (c) 2.4 × 10⁸ m s⁻¹

The refractive index is the ratio of the speeds of light, n = c/v, so v = 3.0 × 10⁸/1.25 = 2.4 × 10⁸ m s⁻¹. 3.75 × 10⁸ (multiplying) would exceed c, which no speed can.

Question 9
The refractive indices of glass and of water with respect to air are 3/2 and 4/3. The refractive index of glass with respect to water is
Show answer

Answer: (d) 9/8

n(glass, water) = n(glass, air) × n(air, water) = (3/2) × (3/4) = 9/8. 8/9 is the index of water with respect to glass.

Question 10
A ray of light passes obliquely through a rectangular glass slab with parallel faces, kept in air. The ray that comes out is
Show answer

Answer: (b) parallel to the incident ray but shifted sideways

Refraction at the two parallel faces gives r2 = i1, so the emergent ray is parallel to the incident ray: there is no deviation, only a lateral shift.

Take the free Class 12 Physics testSee the Class 12 flashcards

← Chapter 8: Electromagnetic WavesChapter 10: Wave Optics →