NDA Redox, metals and non-metals previous year questions with solutions
Redox, metals and non-metals are about one General Studies question in thirty, two or three a sitting. The questions are one-fact recall, with oxidation numbers and three-statement sets rising since 2024. Every question UPSC has set on it since 2017, solved. Grouped by the method each needs, newest first; open a question for its answer and worked solution.
11.1 Oxidation and reduction: definitions, oxidation numbers and the electrochemical series
I. The oxidation number of oxygen in peroxides and superoxides is assigned as –1 and –1/2 respectively.
II. In all its compounds, fluorine has an oxidation number of –1.
III. In a reduction half-reaction, the oxidation number of the reductant decreases.
Which of the statements given above are correct?
Answer and solution
Answer: (a) I and II only
Method. Rules for oxidation numbers
I: O is -1 in peroxides and -1/2 in superoxides, correct (KC7-A41). II: F, the most electronegative element, is always -1, correct (KC7-A44). III: in a reduction half-reaction the oxidation number of the OXIDANT decreases; the reductant's increases, so III is wrong (KC7-A53). So I and II only.
I. Rusting of iron
II. Burning of fuel
III. Rancidity of oils and fats
IV. Browning of fruits
Select the correct answer using the code given below.
Answer and solution
Answer: (d) I, II, III and IV
Method. Oxidation processes
Rusting of iron, burning of fuel, rancidity of oils and fats, and browning of cut fruit (enzymatic oxidation of phenolics by oxygen) are all oxidations (C3-A62, KC7-A04, KC7-A02).
Which of the above pairs are correct?
| (blank) | Reactions | Properties |
|---|---|---|
| I. | Fe(s) + 2HCl(aq) → FeCl_{2}(aq) + H_{2}(g) | Fe is reductant |
| II. | Zn(s) + CuSO_{4}(aq) → ZnSO_{4}(aq) + Cu(s) | Cu is being reduced |
| III. | Br_{2}(l) + 2I^{-}(aq) → 2Br^{-}(aq) + I_{2}(s) | Br_{2} is reductant |
| IV. | CH_{4}(g) + 2O_{2}(g) → CO_{2}(g) + 2H_{2}O(l) | C atom in CH_{4} is oxidized |
Answer and solution
Answer: (c) I, II and IV
Method. Judging oxidant and reductant in each pair
I: Fe 0 -> +2, so Fe is the reductant, correct. II: Cu2+ +2 -> 0, Cu is reduced, correct. III: Br2 0 -> -1 is reduced, so Br2 is the OXIDANT; calling it reductant is wrong. IV: C -4 -> +4, oxidised, correct. So I, II and IV (KC7-A53, KC7-A68).
N2H4 + 2H2O2 → N2 + 4H2O
Answer and solution
Answer: (b) N2H4
Method. Reducing agent by oxidation number
N in N2H4: 2x + 4 = 0, x = -2; in N2: 0. N increases (oxidation), so N2H4 is the reducing agent. In H2O2, O goes from -1 to -2 (reduction), so H2O2 is the oxidising agent (KC7-A53, KC7-A55).
Answer and solution
Answer: (a) Fats and oils in the food get oxidized
Method. Rancidity
Fats and oils left in air are oxidised to foul-smelling aldehydes and acids: rancidity is oxidation (cf. KC7-A02). Standard result.
Answer and solution
Answer: (a) If a substance loses hydrogen during reaction, it is reduced
Method. Classical redox definitions
Loss of hydrogen is OXIDATION, not reduction (KC7-A06, KC7-A09); so (a) is not correct. Loss of oxygen and gain of hydrogen are reduction; gain of oxygen is oxidation (KC7-A04, KC7-A10).
Answer and solution
Answer: (c) Rusting of iron
Method. Oxidation versus physical change
Rusting is oxidation of iron (Fe -> Fe3+ with O2 and moisture) (C3-A61, C3-A62). Freezing, dissolving and boiling are physical changes.
Answer and solution
Answer: (d) + 5
Method. Oxidation number of V in V2O5
2x + 5(-2) = 0, so x = +5 (KC7-A45).
Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)
Which of the following statements about the given reaction is NOT correct?
Answer and solution
Answer: (b) It is highly endothermic reaction
Method. Thermit reaction
Fe2O3 + 2Al -> 2Fe + Al2O3: Al displaces Fe (a, true); Fe +3 -> 0, so Fe2O3 is the oxidising agent (c, true); it is highly EXOTHERMIC and gives molten iron used to weld rail tracks (d, true) (C3-A56). So (b) 'highly endothermic' is the incorrect statement.
Answer and solution
Answer: (a) AlCl3 + 3H2O → Al(OH)3 + 3HCl
Method. Redox test by oxidation number
AlCl3 + 3H2O -> Al(OH)3 + 3HCl is hydrolysis: Al +3, Cl -1, H +1, O -2 throughout, so no redox. 2NaH -> 2Na + H2: Na +1 -> 0, H -1 -> 0, redox. 4Fe + 3O2 -> 2Fe2O3: redox. CuSO4 + Zn -> Cu + ZnSO4: displacement, redox (KC7-A53, KC7-A59).
Answer and solution
Answer: (b) acidified copper sulphate.
Method. Electrolytic refining of copper
Impure copper is the anode, pure copper the cathode, and the electrolyte is acidified CuSO4 solution (C3-A59, T12 TC2-A56).
Answer and solution
Answer: (c) Fe2O3
Method. Oxidation numbers in mixed oxides
Pb3O4 = 2PbO.PbO2 (+2 and +4). Fe3O4 = FeO.Fe2O3 (+2 and +3). Mn3O4 = MnO.Mn2O3 (+2 and +3). Fe2O3: 2x − 6 = 0, Fe is +3 only (KC7-A78, KC7-A79).
Answer and solution
Answer: (a) Zn > Cu > Ag
Method. Electrochemical series
Electron-releasing tendency follows the reactivity: Zn > Cu > Ag (zinc displaces Cu2+, copper displaces Ag+; KC7-A31, KC7-A22, KC7-A27).
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Answer and solution
Answer: (c) Copper is a more reactive metal than iron
Method. Reading a displacement reaction
Fe + CuSO4 -> FeSO4 + Cu: Fe is oxidised (0 -> +2), so it is the reducing agent (a, true); FeSO4 is pale green (b, true); it is redox (d, true). Fe displaces Cu, so iron is the MORE reactive metal; (c) is false (C3-A33, KC7-A61).
Answer and solution
Answer: (c) 2Mg + O2 → 2MgO
Method. Change of oxidation number
2Mg + O2 -> 2MgO: Mg 0 -> +2, O 0 -> -2, so a redox reaction (KC7-A56). The others (neutralisation, hydration of CaO, double decomposition) change no oxidation number.
Answer and solution
Answer: (d) It is an oxidizing agent
Method. Oxidising action of KMnO4
Potassium permanganate is a strong oxidising agent (Mn +7 goes to a lower state, K11 KC7-A95); it oxidises and so destroys organic matter and germs in water. 'It kills germs' states the result, 'oxidizing agent' states the reason asked for ('why').
CH4 + 2O2 → CO2 + 2H2O
Which of the following about the reaction given above is/are correct?
(1) Carbon is oxidized.
(2) Hydrogen is oxidized.
(3) Hydrogen is reduced.
(4) Carbon is reduced.
Select the correct answer using the code given below:
Answer and solution
Answer: (a) 1 only
Method. Oxidation numbers in combustion of CH4
C: -4 in CH4 -> +4 in CO2 (increase = oxidised). H: +1 in CH4 and +1 in H2O (no change). O: 0 -> -2 (reduced). Only statement 1 is correct (KC7-A52, KC7-A53).
11.2 Corrosion: rusting, tarnishing and their prevention
Answer and solution
Answer: (c) Zinc
Method. Galvanisation
Galvanisation coats iron with a thin layer of zinc (C3-A64).
Answer and solution
Answer: (c) silver sulphide
Method. Tarnishing of silver
Silver reacts with H2S/sulphur in air to form black silver sulphide (C3-A61).
Answer and solution
Answer: (b) Zinc
Method. Galvanisation
Iron or steel is coated with zinc, which also protects by sacrificial action (C3-A64).
Answer and solution
Answer: (a) Copper carbonate
Method. Corrosion of copper
Copper reacts with moist CO2 to give the green basic copper carbonate (verdigris) (C3-A61).
Answer and solution
Answer: (a) more electropositive than iron
Method. Sacrificial protection
Zinc lies above iron in the reactivity series, so it is more electropositive and loses electrons more readily; in a scratch it corrodes in place of iron (galvanisation, C3-A64, C3-A79; cf. TC2-A78). Cost, colour and conductivity are not the reason.
Answer and solution
Answer: (b) Iron
Method. Corrosion of iron versus self-protecting metals
Iron in moist air gains a brown, flaky, porous rust that exposes fresh metal, so it corrodes continuously (C3-A61, C3-A62). Aluminium and zinc are covered by a thin, adherent oxide layer that stops further attack (C3-A19). Silver only tarnishes slowly with sulphur (silver sulphide, C3-A61).
11.3 Metals: the reactivity series, extraction and alloys
Answer and solution
Answer: (a) Copper
Method. Early use of elements
Copper was in use from about 9000 BCE (earliest metal worked), gold from about 4000 BCE, whereas oxygen was identified in 1774 and uranium in 1789. Standard historical result; so copper.
Answer and solution
Answer: (d) Steel
Method. Composition of alloys
Steel is iron with carbon (a non-metal). Brass = Cu-Zn, bronze = Cu-Sn, amalgam = Hg with another metal (C3-A65, C3-A66, C3-A69).
Answer and solution
Answer: (b) Iron
Method. Reactivity with cold water
K, Na and Ca all react with cold water to give H2 (C3-A23, C3-A24); iron reacts only with steam (C3-A26).
Answer and solution
Answer: (d) Tin
Method. Stainless steel
Stainless steel is iron with chromium and nickel (and carbon); tin is not a component (C3-A69).
Answer and solution
Answer: (a) Zinc
Method. Extraction by carbon reduction
ZnO is reduced by carbon: ZnO + C -> Zn + CO (C3-A54). Ag and Au occur native or are got by other methods (C3-A46, C3-A50), and Al lies high in the series, so its oxide is reduced electrolytically (C3-A57, C3-A58).
Answer and solution
Answer: (d) Sodium, Iron, Copper, Silver
Method. Reactivity series
Order of decreasing reactivity: Na > Fe > Cu > Ag (C3-A34, KC7-A31).
Answer and solution
Answer: (a) Zinc > Iron > Lead > Copper
Method. Reactivity series
The series reads Zn > Fe > Pb > Cu (Zn and Fe react with steam, Pb and Cu do not react with water at all; C3-A26, C3-A27, C3-A34).
Answer and solution
Answer: (b) Calcium
Method. Reaction of metals with cold water (NCERT Class 10 ch. 3)
Calcium reacts gently with cold water, Ca + 2H2O -> Ca(OH)2 + H2, and starts floating because bubbles of hydrogen stick to its surface (NCERT). Magnesium does not react with cold water; it reacts with hot water and floats then. Potassium reacts so violently that the hydrogen evolved catches fire, so it is never seen floating in cold water even though its density (0.86 g/cm3) is below water's. Copper does not react with water at all. Hence calcium (b).
Answer and solution
Answer: (c) Silver oxide
Method. Thermal decomposition of oxides
Silver oxide decomposes on moderate heating: 2Ag2O -> 4Ag + O2 (oxides of metals low in the series, C3-A50). ZnO and MgO are stable to ordinary heating (reduction needs carbon, C3-A54). Only silver oxide qualifies.
Answer and solution
Answer: (b) Cu and Sn
Method. Alloy composition
Bronze = Cu + Sn; brass = Cu + Zn (C3-A65). Standard result.
Answer and solution
Answer: (c) Mercury
Method. Ores
Cinnabar is HgS, the ore of mercury (C3-A50 on metals low in the series; standard result).
Answer and solution
Answer: (c) Pb and Sn.
Method. Alloy composition
Solder is an alloy of lead and tin (C3-A65 on alloys; standard result).
Answer and solution
Answer: (b) Mixing water to Plaster of Paris
Method. Hydrogen-evolving reactions
Zn + H2SO4 -> ZnSO4 + H2 (C3-A28); Zn + 2NaOH -> Na2ZnO2 + H2 (C3-A16, zinc oxide/zinc is amphoteric); 2K + 2H2O -> 2KOH + H2 (C3-A23). CaSO4.1/2H2O + 1.5H2O -> CaSO4.2H2O is hydration only, no gas.
Answer and solution
Answer: (c) Magnesium (Mg)
Method. Reactivity of metals with water
K and Na react violently with cold water (C3-A23), Ca reacts less violently (C3-A24). Mg does not react with cold water; it reacts only with hot water (C3-A25).
Answer and solution
Answer: (a) Potassium
Method. Liquid-metal coolant
An Na-K alloy is liquid at room temperature and is used as the heat-transfer coolant in nuclear reactors. Standard result.
Answer and solution
Answer: (c) Rubidium
Method. Photoelectric metals
Rubidium (like caesium) has a very low ionisation energy, so light of modest energy ejects electrons: it is used in photoelectric cells. Tungsten, copper and aluminium have high work functions. Standard result.
11.4 Hydrogen, water and hydrogen peroxide
I. Tritium, the isotope of hydrogen, is radioactive and emits low energy alpha particles.
II. In the gas phase, the structure of water is linear.
III. The basic principle of a hydrogen economy is the transportation and storage of energy in the form of liquid or gaseous molecular hydrogen.
Which of the statements given above is/are not correct?
Answer and solution
Answer: (a) I and II only
Method. Properties of hydrogen and water
I is not correct: tritium (3H) is radioactive but emits low-energy beta particles, not alpha. II is not correct: gas-phase water is bent (104.5 degrees), not linear. III is correct: the hydrogen economy stores and transports energy as liquid or gaseous H2 (TC2-A79). The question asks for the statements that are not correct: I and II only.
I. A 30% solution of hydrogen peroxide is marketed as ‘10 volume’ H2O2.
II. In the compound copper sulphate pentahydrate, all the five water molecules are hydrogen bonded.
Which of the statements given above is/are correct?
Answer and solution
Answer: (d) Neither I nor II
Method. Hydrogen peroxide strength and hydrated salt
I: volume strength = litres of O2 from 1 L of solution. 30% w/v = 300 g/L = 300/34 = 8.82 mol/L; 2H2O2 -> 2H2O + O2 gives 11.2 L O2 per mole, so 8.82 x 11.2 = 98.8, i.e. about 100 volume. 10 volume is about 3%. I is false. II: in CuSO4.5H2O four water molecules are coordinated to Cu2+ and the fifth is hydrogen bonded to sulphate and the coordinated waters, so not all five are H-bonded as stated; II is false. Neither (cf. K11 hydrogen peroxide: 30% as 100 volume; standard, pre-2023 NCERT).
Answer and solution
Answer: (d) Rain water
Method. Purity of natural waters
Rain water is formed by evaporation, i.e. natural distillation, so it carries the least dissolved matter; river, well and sea water contain dissolved salts. Standard result.
Answer and solution
Answer: (b) Latent heat of fusion of water is very low.
Method. Properties of water
Specific heat of water is abnormally high (4.18 J/g/K) (a true); water is denser than ice (c true); pure water is a poor conductor (d true). The latent heat of fusion of water (about 334 J/g) is high, not low; so (b) is not correct. Standard result.
Answer and solution
Answer: (d) Colourless
Method. Physical property of hydrogen
Hydrogen is a colourless, odourless gas. Standard fact.
Answer and solution
Answer: (d) A mixture of NO2 and H2 is known as Syngas.
Method. Properties of dihydrogen
(a) is true; (b) true, H-H bond enthalpy 436 kJ/mol; (c) true: 2Na + H2 -> 2NaH. (d) false: syngas (water gas) is CO + H2, not NO2 + H2. Standard (pre-2023 NCERT).
Answer and solution
Answer: (c) non-stoichiometric hydrides.
Method. Hydrogen storage
Non-stoichiometric (interstitial) hydrides of d-block metals such as Pd absorb very large volumes of H2; they are the hydrogen-storage medium. Alkali-metal hydrides are stoichiometric ionic solids, non-metal hydrides are molecular. Standard result (pre-2023 NCERT).
11.5 Carbon, nitrogen and oxygen: the common gases and their oxides
I. Nitrogen contains a triple bond.
II. Nitrogen is a triatomic gas.
III. Forces acting between nitrogen molecules are weak van der Waals forces.
Which of the statements given above are correct?
Answer and solution
Answer: (c) I and III only
Method. Nitrogen molecule
I: N2 has the triple bond N≡N, correct. II: N2 is diatomic, so II is false. III: only weak van der Waals (London) forces act between N2 molecules (hence its very low boiling point), correct. So I and III. Standard result (pre-2023 NCERT).
Answer and solution
Answer: (a) CO
Method. Neutral oxides
CO is neutral, neither acidic nor basic. CO2 is acidic; Na2O and MgO are basic (C3-A15, C3-A70).
Answer and solution
Answer: (b) CO2
Method. Dry ice
Dry ice is solid CO2. Standard fact.
Answer and solution
Answer: (b) NO2
Method. Dimerisation of oxides of nitrogen
NO2 (odd-electron, paramagnetic brown gas) dimerises to colourless N2O4 on cooling: 2NO2 <-> N2O4. N2O, N2O3 and N2O5 are not odd-electron molecules. Standard result (pre-2023 NCERT).
Answer and solution
Answer: (b) Haber-Bosch process
Method. Industrial synthesis of ammonia
Haber-Bosch process: N2 + 3H2 <-> 2NH3 over iron catalyst. Ostwald's process makes HNO3 from NH3. Standard result (pre-2023 NCERT).
Answer and solution
Answer: (c) Solid state of carbon dioxide
Method. Dry ice
Dry ice is solid carbon dioxide, which sublimes. Standard fact.
Answer and solution
Answer: (c) the reaction is endothermic and requires very high temperature
Method. Reaction of N2 with O2
N2 + O2 -> 2NO is endothermic (+180 kJ/mol) and needs about 3000 K or an electric arc, because the N-N triple bond is very strong; hence air does not react at ordinary temperature. Standard result (pre-2023 NCERT).
Answer and solution
Answer: (a) 3Cu + 8HNO3 (dilute) →
Method. Products of metal + nitric acid
3Cu + 8HNO3 (dilute) -> 3Cu(NO3)2 + 2NO + 4H2O gives NO. Conc. HNO3 with Cu or Zn gives NO2; dilute HNO3 with Zn gives N2O or NH4NO3. HNO3 is an oxidising acid and gives no H2 (C3-A29). Standard result.
Answer and solution
Answer: (a) Solid carbon dioxide
Method. Dry ice
Solid CO2 sublimes without leaving a liquid, hence 'dry ice'. Standard fact.
Answer and solution
Answer: (b) ability to form a complex with haemoglobin
Method. Toxicity of carbon monoxide
CO binds to the iron of haemoglobin about 200 times more strongly than O2, forming carboxyhaemoglobin and blocking oxygen transport. Standard result (pre-2023 NCERT).
11.6 Halogens, noble gases, sulphur and phosphorus
Answer and solution
Answer: (b) helium
Method. Gas mixtures for divers
Nitrogen dissolves in blood under pressure and causes narcosis and bends; helium is much less soluble, so a He-O2 mixture is used. Chlorine and ozone are toxic. Standard result.
Answer and solution
Answer: (b) HOBr
Method. Naming of oxoacids of bromine
HOBr (HBrO) is hypobromous acid. HBrO3 is bromic, HBrO4 perbromic, HBr hydrobromic. Standard nomenclature.
Answer and solution
Answer: (c) Both contain chlorine
Method. Constitution of bleaching powder and DDT
Bleaching powder is CaOCl2 (inorganic, contains Ca and Cl). DDT is C14H9Cl5 (organic, contains Cl, no Ca). The only common feature is chlorine. Standard result.
Answer and solution
Answer: (a) in etching glass
Method. Chemistry of hydrofluoric acid
HF attacks silica and silicates of glass (SiO2 + 4HF -> SiF4 + 2H2O), so its textbook use is etching glass. It is a weak acid, not a bleach or a strong oxidising agent. Standard reference (pre-2023 NCERT).
List I (Noble gas)
(A) Argon
(B) Neon
(C) Krypton
(D) Xenon
List II (Use)
(1) In lights for advertising display
(2) Airport landing lights and in light houses
(3) Light in photographer's flash gun
(4) In tungsten filament to last longer
Code:
A B C D
Answer and solution
Answer: (d) 4 1 2 3
Method. Uses of noble gases
Argon: inert fill in tungsten filament bulbs so the filament lasts longer (4). Neon: advertising display tubes (1). Krypton: airport landing lights and lighthouses (2). Xenon: photographer's flash guns (3). So A-4, B-1, C-2, D-3. Standard noble-gas uses (pre-2023 NCERT, standard reference).
Answer and solution
Answer: (a) an inert gas
Method. Group 18 gases
Radon (Z = 86) is the heaviest noble (inert) gas, a radioactive product of the decay of radium. It is neither a fibre, an explosive nor a metal. Standard result (pre-2023 NCERT).
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