Class 10 Maths Chapter 10: Circles MCQs with answers
10 multiple-choice questions on Circles, each with its answer and the reason, written from the NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (c) a tangent
A line that meets a circle in exactly one point is a tangent, and K is its point of contact.
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Answer: (b) 1
OP = 6 cm equals the radius, so P lies on the circle. At a point on the circle there is exactly one tangent.
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Answer: (c) a line that does not meet the circle
The distance 7 cm is greater than the radius 6.5 cm, so every point of l lies outside the circle: l and the circle have no common point.
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Answer: (b) A circle has infinitely many tangents, but only two of them pass through a given point outside it.
There is one tangent at every point of the circle, so infinitely many in all; through a point outside the circle exactly two of them pass, and through a point inside, none.
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Answer: (a) 38°
The tangent is perpendicular to the radius, so ∠OPT = 90°. In ΔOPT, ∠OTP = 180° − 90° − 52° = 38°.
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Answer: (a) 15 cm
The right angle is at the point of contact, so the tangent length is √(17² − 8²) = √225 = 15 cm.
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Answer: (b) 37 m
The radius to the point of contact is perpendicular to the lane, so the distance from K to the centre is the hypotenuse: √(35² + 12²) = √1369 = 37 m. (√(35² − 12²) treats the distance as a leg.)
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Answer: (c) 35 cm
OP = PC + OC = 25 + 12 = 37 cm. The tangent length is PA = √(37² − 12²) = √1225 = 35 cm, measured to the point of contact, not to C or to the far side.
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Answer: (a) 4
Tangents from an external point are equal: 3x + 1 = 5x − 7, so 2x = 8 and x = 4.
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Answer: (b) 120°
OP = OQ = PQ, so ΔOPQ is equilateral and ∠POQ = 60°. ∠PTQ and ∠POQ are supplementary: ∠PTQ = 180° − 60° = 120°.
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