Class 10 Maths Chapter 9: Some Applications of Trigonometry MCQs with answers
10 multiple-choice questions on Some Applications of Trigonometry, each with its answer and the reason, written from the NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
Show answer
Answer: (a) the line of sight and the horizontal through the observer's eye
Both angles of elevation and depression are measured from the horizontal through the eye, up to the line of sight. Option (d) measures from the vertical, which is the usual slip.
Show answer
Answer: (b) angle of depression
The scooter is below the horizontal level of her eye, so the angle her line of sight makes with the horizontal is an angle of depression.
Show answer
Answer: (c) line of sight
By definition this line is the line of sight; the angles of the chapter are measured between it and the horizontal.
Show answer
Answer: (a) 18 m
tan 45° = height / 18 and tan 45° = 1, so the height is 18 m. (18√3 m comes from wrongly using tan 60°, 6√3 m from tan 30°.)
Show answer
Answer: (c) 7 m
The escalator is the hypotenuse and the height is opposite the 30° angle, so height = 14 sin 30° = 14 × 1/2 = 7 m. 7√3 m is the horizontal run (cos 30°).
Show answer
Answer: (b) the distance from the foot of the chimney and the angle of elevation of its top
A height is found from one right triangle: the horizontal distance from the foot, the angle of elevation, and the observer's own height. An angle alone or a distance alone does not fix the triangle.
Show answer
Answer: (b) 30°
In the right triangle formed by the cliff, the sea and the line of sight, the angle at the cliff-top is 90° − 30° = 60°, so the angle at the boat is 180° − 90° − 60° = 30°. The depression and the elevation are alternate angles, hence equal.
Show answer
Answer: (d) 45°
tan θ = height / shadow = 1, and tan 45° = 1, so θ = 45°.
Show answer
Answer: (c) 60°
tan θ = height / shadow = √3, and tan 60° = √3, so θ = 60°. (30° is what one gets by inverting the ratio.)
Show answer
Answer: (b) tan θ = hd
h is the side opposite θ and d is the side adjacent to it; both are legs of the right triangle, so the ratio relating them is tan θ = h/d.
← Chapter 8: Introduction to TrigonometryChapter 10: Circles →