Class 11 Physics Chapter 2: Motion in a Straight Line MCQs with answers
10 multiple-choice questions on Motion in a Straight Line, each with its answer and the reason, written from the NCERT chapter. For school exams on the CBSE pattern, JEE Main and NEET, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (b) the size of the bus is much smaller than the distance it moves
A body may be treated as a point object when its size is much smaller than the distance it moves in the time considered; a bus about 10 m long covering 60 km qualifies. Speed, mass and the shape of the road do not decide this.
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Answer: (c) the slope of the tangent to the graph at that instant
Velocity is the limit of Δx/Δt as Δt → 0. The chord through two points of the graph becomes the tangent in this limit, so the velocity is the slope of the tangent at that instant. The slope of the line from the origin gives only the average velocity from t = 0.
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Answer: (a) 100 m
Let the westward run be w. Path length = 300 + w; magnitude of displacement = 300 − w. Both are divided by the same time, so 300 + w = 2(300 − w), 3w = 300 and w = 100 m.
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Answer: (d) −5 m s⁻²
ā = (v₂ − v₁)/(t₂ − t₁) = (−4 − 6)/2 = −5 m s⁻², that is, 5 m s⁻² towards the west. Taking −1 m s⁻² ignores the reversal of direction.
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Answer: (a) The ball's velocity changed, so it was accelerated during the contact.
Velocity has magnitude and direction. The speed stayed 3 m s⁻¹ but the velocity changed from +3 m s⁻¹ to −3 m s⁻¹, a change of 6 m s⁻¹; a change in velocity in any time means an acceleration.
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Answer: (b) negative
The slope of the x-t graph is the velocity. A curve bending downward has a decreasing slope, so the velocity decreases and the acceleration is negative; a straight line would mean zero acceleration.
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Answer: (c) 40 m
Displacement is the area under the v-t line, a trapezium: ½ (4 + 12) × 5 = 40 m. Using only the final velocity (12 × 5) gives 60 m and only the initial velocity gives 20 m.
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Answer: (d) a parabola, and a straight line inclined to the time axis
For uniform acceleration x = ½at² (a parabola) and v = at (a straight line through the origin, inclined to the time axis). The pair in option (a) describes uniform motion.
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Answer: (c) displacement
In one dimension the sign of displacement shows its direction, so it can be negative. Path length, speed and average speed are magnitudes or totals of path and are never negative.
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Answer: (b) the same as just before it stopped, directed down the track
The trolley moves with a constant acceleration down the track throughout; zero velocity at an instant does not mean zero acceleration. If the acceleration were zero at that instant, the trolley would stay at rest instead of rolling back.
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