Class 11 Physics Chapter 3: Motion in a Plane MCQs with answers
10 multiple-choice questions on Motion in a Plane, each with its answer and the reason, written from the NCERT chapter. For school exams on the CBSE pattern, JEE Main and NEET, which are set from the same NCERT chapter. Open a question's solution to check your working; then take the free test to find your next chapter.
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Answer: (b) P ≠ Q, since their directions differ
Two vectors are equal only if they have the same magnitude and the same direction. P and Q have equal magnitudes but different directions, so P ≠ Q.
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Answer: (d) magnitude 10 units, pointing west
Multiplying by a negative number −λ reverses the direction and multiplies the magnitude by λ: |−2.5A| = 2.5 × 4 = 10 units, pointing west.
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Answer: (a) (3î − 4ĵ)/5
n̂ = A/|A|, and |A| = √(3² + 4²) = 5, so n̂ = (3î − 4ĵ)/5. Dividing by 25 uses |A|², and 7 adds the components instead of using Pythagoras.
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Answer: (c) −10√3
Ax = A cos θ = 20 cos 150° = 20 × (−√3/2) = −10√3 N. The component is negative because the force points to the left of the y-axis; −10 is A sin θ with the wrong sign.
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Answer: (c) 5
Rx = 2 + (−5) = −3, Ry = 3 + 1 = 4, so |R| = √(9 + 16) = 5. √53 is |A − B|, and 7 adds the magnitudes of the components.
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Answer: (b) along the tangent to its path, in the direction of motion
Velocity is the limit of Δr/Δt as Δt → 0; in this limit Δr lies along the tangent, so the velocity is tangent to the path at that point, in the direction of motion.
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Answer: (c) can have any value from 0° to 180°
Only in one dimension are velocity and acceleration along one line. In two or three dimensions the angle between them may be anything from 0° to 180°.
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Answer: (d) the horizontal component of its velocity
The only acceleration is g, vertically downward, so ax = 0 and vx = v₀ cos θ₀ stays constant. The vertical component changes at the rate g, so the speed and the velocity change too.
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Answer: (a) of constant magnitude, always directed towards the centre, so it is not a constant vector
The velocity keeps changing direction, so there is an acceleration, v²/R, towards the centre. Its magnitude is constant but its direction turns with her, so it is not a constant vector.
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Answer: (d) 1 : 3
Every point of the disc has the same ω, and v = Rω, so vA : vB = 5 : 15 = 1 : 3. 1 : 1 would be the ratio of angular speeds; 1 : 9 wrongly squares the ratio of the radii.
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